A 290-kg flatcar 28 m long is moving with a speed of 6.5 m/s along horizontal frictionless rails. A 95-kg worker starts walking from one end of the car to the other in the direction of motion, with speed 3.0 m/s with respect to the car. In the time it takes for him to reach the other end, how far has the flatcar moved?

9.33 seconds

60.67 meters

Step-by-step explanation:

A worker with a speed of 3.0 m/s with respect to a car, starts to walk from one end of the car to the other in the direction of motion of the car.

As the car is 28 m long, then the worker will reach the other end of the car in seconds. (Answer)

Now, the car is moving with a speed of 6.5 m/s and in the time of 9.33 seconds, it will move by meters. (Answer)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: