A piece of rope is made up of 100 strands. Assume that the breaking strength of the rope is the sum of the breaking strengths of the individual strands. Assume further that this sum may be considered to be the sum of an independent trial process with 100 experiments each having an expected value of 10 pounds and standard deviation Find the approximate probability that the rope will support a weight
a. of 1000 pounds.
b. of 970 pounds.

a. of 1000 pounds. P=0.5

b. of 970 pounds. P=0.99865

Step-by-step explanation:

The question is incomplete: the standard deviation is 1.

The strength of the rope is the sum of the strengh of the 100 strands that make the rope. If the strands have a mean strength of 10 and a standard devition of 1, the strength of the rope will have the following mean and standard deviations:

We can calculate then, the probability that the rope will support a weight of 1000 pounds:

The probability that the rope will support a weight of 970 pounds is:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35