Lily bought 6 skirts and 5 coats for a total of $452.62. if lily sister bought 3 skirts and 5 coats for $289.36, what was the price of one coat? $(round to the nearest cent)

$26.02

Step-by-step explanation:

Let the price of a skirt be A and that of coat be B

Iilly bought 6 skirts and 5 coats for a total of $452.62

That’s

6A + 5B = 452.62

Also, Lilly’s sister bought 3 skirts and 5 coats for $289.36

That’s

3A + 5B = 289.36

We now have two equations

1 . 6A + 5B = 452.62

2. 3A + 5B = 289.36

Subtract equation two from equation one

We have

3A = 163.26

Divide both sides by 3

3A/3 = 163.26/3

A = 54.42

A = $54.42

Now substitute 54.42 for A in either equations to get B the price of a coat

Using equation one, we have

6A + 5B = 452.62

6 x 54.42 + 5B = 456.62

326.52 + 5B = 456.62

Subtract 326.52 from both sides

326.52 - 326.52 + 5B = 456.62 - 326.52

5B = 130.1

Divide both sides by 5

5B/5 = 130.1/5

B = 26.02

= $26.02

A coat cost $26.02

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9