I have a coil of steel that is 48 inches wide. The weight of the coil is 10.800 kegs. If I cut the coil a width of 0.5 inches how much will the 0.5 inch coil weigh. Can you show me an example on how to figure this problem out.

0.1125 kg

Step-by-step explanation:

Step 1:

Let us assume that 48 inches of coil of steel weighs 10.800 kg.

We have to find the weight of 0.5 inch coil.

Step 2:

In this problem we assume that it is given in direct relationship.

Therefore, Problem becomes

48 inches weigh 10.8 kg

0.5 inches weigh X kg

(48 / 0.5) = ( 10.8 / X)

X =  (10.8 × 0.5) / 48

X =  0.1125 kg

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

probability for j is 1/4

while

a is 1/6