3 ( 1 + 2b) + 2 < 71

b < 11

Step-by-step explanation:

Step 1:  Distribute

3(1 + 2b) + 2 < 71

(3 * 1) + (3 * 2b) + 2 < 71

3 + 6b + 2 < 71

Step 2:  Combine like terms

3 + 6b + 2 < 71

5 + 6b < 71

Step 3:  Subtract 5 from both sides

5 + 6b - 5 < 71 - 5

6b < 66

Step 4:  Divide both sides by 6

6b / 6 < 66 / 6

b < 11

 b < 11

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

goog may be able to you find that answer