How to factor x^3 - 4x^2 - 9x + 36 by grouping

(x-4) (x-3) (x+3)

Step-by-step explanation:

x^3 - 4x^2 - 9x + 36

Make 2 groups

x^3 - 4x^2            - 9x + 36

We can factor out x^2 from the first group and -9 from the second group

x^2 (x-4)    - 9(x-4)

Now factor out (x-4)

(x-4) (x^2 -9)

This may be an answer choice but we can still factor

(x^2 -9) is the difference of squares

(x^2-9) = (x-3) (x+3)

Replacing this

(x-4) (x-3) (x+3)

(x - 4)(x - 3)(x + 3)

Step-by-step explanation:

x³ - 4x² - 9x + 36

x²(x - 4) - 9(x - 4)

(x - 4)(x² - 9)

(x - 4)(x² - 3²)

(x - 4)(x - 3)(x + 3)

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.