Oula is going on an outdoor expedition with his family. The expedition will include a hunting event, a fishing event, a hiking event, and a camping event. There are 4 hunting, 7 fishing, 6 hiking, and 3 camping events for Oula's family to choose from.

We can have 504 difference outdoor expeditions possible.

Step-by-step explanation:

We have , Oula is going on an outdoor expedition with his family. The expedition will include a hunting event, a fishing event, a hiking event, and a camping event. There are 4 hunting, 7 fishing, 6 hiking, and 3 camping events for Oula's family to choose from. We need to find how many difference outdoor expeditions possible. Let's find out:

According to question , Number of events are

We can solve problems like this using multiplication rules. Since the order of events in the expedition does not matter, we can multiply all numerical values in any order we so choose.  

⇒

⇒

Therefore , We can have 504 difference outdoor expeditions possible.

ik how do do this just give me a few minutes and i will give it to

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.