(1901+1902+1903+...+1993)-(101+102+ 103+...+193)=

165600

Step-by-step explanation:

(1901+1902+1903+...+1993) - (101+102+103+...+193)=

(1901-101)+(1902-102)+...+(1993-193)=

1800+1800+...+1800=(We have a series of 92 numbers)

92*1800=165600

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p