Find hcf and lcm of 120 and 140 by using fundamental theorem of arithmetic

20 and 4200

Step-by-step explanation:

Express the numbers as products of their prime factors.

120 = 2 × 2 × 2 × 3 × 5

140 = 2 × 2 × 5 × 7

Identify the prime factors that both numbers have in common and multiply them.

both have 2, 2 and 5, thus

HCF = 2 × 2 × 5 = 20

Multiply each factor the greatest number of times it occurs in either number.

2 : 3 times

3 : 1 time

5 : 2 times

7 : 1 time

LCM = 2 × 2 × 2 × 3 × 5 × 5 × 7 = 4200

HCF = 20

LCM = 840

Step-by-step explanation:

120 = 2×2×2×3×5

140 = 2×2×5×7

HCF: 2×2×5 = 20

LCM: 140×2×3 = 840

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x