A number m is such that when it is divided by 30,36 and 45, the remainder is always 7.Find the smallest possible value of m

  187

Step-by-step explanation:

The desired number will be 7 more than the least common multiple (LCM) of 30, 36, and 45.

30 and 36 have a greatest common factor of 6, so their least common multiple will be 30×36/6 = 180. This is also a multiple of 45, so 180 is the LCM of all three numbers. Seven more than this is 187.

The smallest possible value of m is 187.

Comment on the answer

Actually, the answer could be m = 180n +7, where n is any integer. If negative values of n are allowed, there is no "smallest", as the numbers tend toward negative infinity. For n=0, m will be 7, which will give the specified remainders. The quotient in each case will be 0, which may not be what you want. The above answer assumes n > 0.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints