A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.
Given that a(2) = 0, what is the absolute value of the product of the zeros of a?

the absolute value of the product of the zeros of a is .

Step-by-step explanation:

Here we have , is a polynomial function of t, where k is a constant.  Given that a(2) = 0 . We need to find the  absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

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But , t=2 So ,  . Now , the absolute value of the product of the zeros of a is :

⇒

⇒

⇒

Therefore, the absolute value of the product of the zeros of a is .

it's both, now can you answer my most recent question?

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.