1. To approach the runway, a small plane must begin a 6° descent starting from a height of 1000 feet above the ground. To the nearest foot, how many feet from the runway is the airplane at the start of this approach?

The plane was 9514 ft. distant from the runway.

Step-by-step explanation:

See the attached diagram.

Now, B is the initial position of the plane which is 1000 ft. above A.

Now, Δ ABC is a right triangle having ∠ ACB = 6°

So, applying trigonometry, we can write

⇒ x = 9514.36 ≈ 9514 ft.

Therefore, the plane was 9514 ft. distant from the runway. (Answer)

idk sry

step-by-step explanation:

30 feet

step-by-step explanation:

that would be 2 1/2 * 12

= 24 + 6

= 30 feet   (answer)