Solve the triangle. a = 12, b = 22, c = 95°

c = 26 , ∠A = 27.38° and ∠B = 57.62°

Step-by-step explanation:

Given:

a = 12 , b = 22  and ∠C = 95°

To find: c , ∠A and ∠B

We use Law of cosine and Law of sine to solve the triangle.

Law of cosine states that c² = a² + b² - 2ab cos C

Law of sines states that

Now, using Law of cosine,

c² = 12² + 22² - 2(12)(22) cos 95

c² = 144 + 484 - 528(-0.087)

c² = 628 + 45.9

c² = 673.93

c = 25.96 ≈ 26

Now using Law of sines

Therefore, c = 26 , ∠A = 27.38° and ∠B = 57.62°

c ≈ 26, A ≈ 27.6°, B ≈ 57.4°

 c ≈ 26, A ≈ 54.4°, B ≈ 30.6°

 c ≈ 25.1, A ≈ 27.6°, B ≈ 57.4°

 c ≈ 25.1, A ≈ 31.6°, B ≈ 53.4° 

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

table 3 represents a direct variation function. : )