The Statistical Bulletin published by Metropolitan Life Insurance Co. reported that 2% of all American births result in twins. If a random sample of 8000 births is taken, find the mean, variance, and standard deviation of the number of births that would be result in twins

mean = 160

Variance = 156.8

Standard deviation = 12.52

Step-by-step explanation:

This is solved by the binomial distribution model for approximation.

n = number of random sample in which for this question, n= 8000

p = probability of success = 2% = 0.02

Mean of the sample = Expected value which approximates the average number of cases to expect from the larger sample chosen.

Mean = np = 0.02 × 8000 = 160

Variance = np(1-p) = 160(1-0.02) = 156.8

Standard deviation = √variance = √156.8 =12.52

c = 0.429t

step-by-step explanation:

the constant rate at which carlos harvests cassava is 35 minutes per 15 cassavas 15/35 = 0.429 cassava per minute

therefore, an equation that models the number of cassava (c) that harvest carlos in a time (t) is the following:

where t is the time in minutes.

this means that when 35 minutes have elapsed 15 cassava have been harvested, at 70 minutes 30 cassava have been harvested and so on.