x^2 + 6x + y^2 + 4y + 12 = 0
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Mathematics, 20.03.2020 18:31 Aliciaonfleek
Find the center and the radius of the circle with the equation:
x^2 + 6x + y^2 + 4y + 12 = 0
a.
center: (3, 2)
radius: 1
c.
center: (6, 4)
radius: 12
b.
center: (-3, -2)
radius: 1
d.
center: (-6, -4)
radius: 12
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Answers: 1
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You know the right answer?
Find the center and the radius of the circle with the equation:
x^2 + 6x + y^2 + 4y + 12 = 0
x^2 + 6x + y^2 + 4y + 12 = 0
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