An airline company purchased two new airplanes. One can travel at speeds of up to 600 miles per hour and the other at speeds of up to 720 miles per hour. How many more miles can the faster airplane travel in 12 seconds than the slower airplane?

0.4miles

Step-by-step explanation:

Given parameters:

Speed of A = 600miles/hour

Speed of B = 720miles/hour

Time of consideration  =  12seconds

Unknown:

The number of distance B travels over A = ?

Solution:

To solve this problem, we are going to find the distances both airplanes will cover within the given time.

  Distance  = speed x time

Convert the time from seconds to hours ;

                3600s  = 1hr

                   12s  =   = 0.0033hr

Distance that would be covered by A = 600miles/hour x 0.0033hr = 2miles

Distance that would be covered by B = 720 miles/hour x 0.0033hr = 2.4miles

The faster airplane will cover a distance 2.4 - 2.0 = 0.4miles than the slower plane

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.