Could anyone please help me solve these equations?

5r+8=2(5+3r)

-2(8x+6)+2=-40-x

-16+4x<2(1-x)

4x-34 greater than or equal to -2(2x-7)

-4|6-3v|=-36

-6-10|2a+9|<-56

Step-by-step explanation:

1) 5r+8=2(5+3r)

5r+8=10+6r

-10+8=-5r+6r

-2 = r

2) -2(8x+6)+2=-40-x

-16x-12+2=-40-x

-16x-10=-40-x

-16x+x=-40+10

-15x=-30

x= = 2

3) -16+4x<2(1-x)

-16+4x < 2-2x

4x-2x< -16-2

-18 < -6x

x < 3

4) 4x-34 greater than or equal to -2(2x-7)

4x-34= -4x+14

4x=-4x+48

8x=48

x=6

5) -4|6-3v|=-36

|6-3v|=9

6-3v=-9  or  6-3v=9

v=-1      or     v=5

6) -6-10|2a+9|<-56

-10|2a+9|<-50

10|2a+9|>50

|2a+9|>5

2a+9<-5  or   2a+9>5

a< -7        or   a> -2

attachment?

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form