Which is an equation of the line that passes
through the point (1,4) and has a slope of 3?

y = 3x + 1

Step-by-step explanation:

We are asked to find the equation of a line

Step1: find the slope

We are provided with the slope already in the question

Slope m = 3

Step 2: substitute slope into intercept form equation

y = mx + c

m = 3

y = 3x + c

Step 3: substitute the point into the equation

( 1 , 4)

x - 1

y - 4

y = 3x + c

4 = 3(1) + c

4 = 3 + c

c = 4 - 3

c = 1

Step 4: substitute c = 1 into the equation

y = mx + c

y = 3x + 1

The equation of the line is

y = 3x + 1

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.