A box is filled with 2 blue cards, 4 brown cards, and 6 yellow cards. A card is chosen at random from a box. What is the probability that the card is not brown?

Therefore the probability that the card is not brown is .

Step-by-step explanation:

Probability: Probability is the ratio of the favorable outcome to the total outcome.

Given that, a box contains  2 cards blue in color , 4 cards brown in color and 6 cards yellow in color.

Total number of cards= (2+4+6)=12

∴P(getting a brown card)

∴P(not getting a brown card)

=1 - P(getting a brown card)

Therefore the probability that the card is not brown is .

2/3

Step-by-step explanation:

hey there!

so our first step is to find the total number of cards

2+4+6=12

now we have to find the number of cards that are not brown

2+6=8

the probability would be 8/12

this can be simplified to 2/3 by dividing the numerator and denominator by 4

2/3 is also equal to 66.67%

your answer is b ^w^ hope i

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %