A mint produces 150000 souviner coins each year. In a random sample of 400 coins, 3 have a misprint. Predict the number of coins that will have misprints in a year

1125 coins

Step-by-step explanation:

To predict the number of coins with problem, we assume that for each 400 of the 150000 coins, we have 3 with misprint.

So, using rule of three, if 400 coins have 3 coins with problems, 150000 coins have X coins with problem:

400 -> 3

150000 -> X

400/150000 = 3/X

X = 150000*3/400 = 1125

We predict that 1125 coins will have a misprint.

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer

im not sure

step-by-step explanation: