Determine the center and radius of the following circle equation:
x^2+y^2-6x-8y+24=0

Center is (3, -4) and radius is 1

Step-by-step explanation:

The standard form of the equation of a circle is x² + y² + 2gx +2fy + c = 0, where center is (-g, -f) and radius = √g² + f² - c

By comparing the 2 equations, 2g = -6, 2f = 8 and c = 24

⇒ g = -6/2 = -3

⇒ f = 8/2 = 4

⇒ c = 24

Center = (-g. -f) = (3, -4)

Radius = √g² + f² - c = √3² + (-4)² - 24

           = √9 + 16 - 24 = √1 = 1

what? that isnt a question

step-by-step explanation: