Suppose the cumulative distribution function of the random variable X is Round your answers to 3 decimal places. Determine the following: a) b) c) d) Statistical Tables and Charts

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Full Question

Suppose the cumulative distribution function of the random variable X is F(x) = 0.25x + 0.4

For {0, x < -1.6; -1.6 ≤ x ≤ 2.4; 1, x ≥ 2.4}

(Round your answers to 3 decimal places) Determine the following:

1. P(X < 1.8)

2. P(X> - 1.5)

3. P(X < - 2)

1. P(X<1.8) = 0.85

2. P(X> - 1.5) = 0.975

3. P(X < - 2) = 0

Step-by-step explanation:

1. Calculating P(X < 1.8);

Since, F(x) = 0.25x + 0.4

P(X<1.8) = 0.25(1.8) + 0.4

P(X<1.8) = 0.85 or 85%

2. Calculating P(X> - 1.5)

Here

P(X> - 1.5) + P(X≤-1.5) = 1

P(X> - 1.5) = 1 - P(X≤-1.5)

Calculating P(X≤-1.5)

P(X≤-1.5) = 0.25(-1.5) + 0.4

P(X≤-1.5) = 0.025

So,

P(X> - 1.5) = 1 - 0.025

P(X> - 1.5) = 0.975

3. Calculating P(X < - 2)

X < -2 doesn't fall within the range of values given in (question) above.

So, P(X < - 2) = 0

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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