Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals). a. The area to the left of is . b. The area to the left of is . c. The area to the right of is . d. The area between and is . (Hint: Enter the positive z-value)

a) z=0.845

b) z=1.185

c) z=-0.925

d) z=1.881

Step-by-step explanation:

The question is incomplete.

Given that is a standard normal random variable, find for each situation (to 2 or 3 decimals).

a. The area to the left of z is 0..8 .  z=0.845

b. The area to the left of z is 0.882 .  z=1.185

c. The area to the right of z is 0.8225 .  z=-0.925

d. The area between -z and z is 0.94.  z=1.881 (Hint: Enter the positive z-value)

2x^2+5x+17

your welcome. : )

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.