A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random sample of 235 cartridges is selected, and each cartridge is inspected. If the sample proportion of defective cartridges is more than 0.02, the entire shipment is returned to the vendor. (a) What is the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05?(b) What is the approximate probability that a shipment will not be returned if the true proportion of defective cartridges in the shipment is 0.10?

Note, that the population proportion is p=0.05

So for n=200n the mean of pˆ is,

μpˆ=p=0.05

Therefore, for n=200 the standard deviation of pˆ is,

σpˆ=√(0.05)(1−0.05)/200

= √(0.05)(0.95)/200

= √0.0475/200

=√0.0002375

≈0.0154

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752