What is the line with a slope of 3/2 that contains the point (-4,-2)

y = 3/2x + 4

Step-by-step explanation:

First, write your current equation: y= 3/2x + b. Plug in your point to the equation to get this: -2 = 3/2(-4) + b. Multiply 3/2 by -4 to get -6. This is what is should look like: -2 = -6 + b. Add 6 to both sides to get your y-intercept of 4. Go back to your original equation and plug in 4 to b. This is your final equation: y = 3/2x + 4. Hope this helped!

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

answer: 414,377,008

step-by-step explanation:

just multiply it