Find the solution to each of these recurrence relations with the given initial conditions. Use an iterative approach such as that used in Example 10. a) an = −an−1, a0 = 5 b) an = an−1 + 3, a0 = 1 c) an = an−1 − n, a0 = 4 d) an = 2an−1 − 3, a0 = −1 e) an = (n + 1)an−1, a0 = 2 f ) an = 2nan−1, a0 = 3 g) an = −an−1 + n − 1, a0 = 7

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph