The other expression that has a value of
is A) sin B.
Step-by-step explanation:
Step 1:
![sin\theta = \frac{oppositeside}{hypotenuse} ,](/tpl/images/0554/6009/9f110.png)
![cos\theta = \frac{adjacentside}{hypotenuse} ,](/tpl/images/0554/6009/d8c65.png)
![tan \theta = \frac{opposite side}{adjacent side} .](/tpl/images/0554/6009/e7ffd.png)
For angle B, the opposite side measures 7 units, the adjacent side measures 24 units and the hypotenuse measures 25 units.
![sinB= \frac{oppositeside}{hypotenuse} = \frac{7}{25} ,](/tpl/images/0554/6009/8b603.png)
![tan B = \frac{opposite side}{adjacent side} = \frac{7}{24} ,](/tpl/images/0554/6009/3a386.png)
![cosB = \frac{adjacentside}{hypotenuse} = \frac{24}{25}.](/tpl/images/0554/6009/5da2a.png)
Step 2:
For angle A, the opposite side measures 24 units, the adjacent side measures 7 units and the hypotenuse measures 25 units.
![tan A = \frac{opposite side}{adjacent side} = \frac{24}{25} .](/tpl/images/0554/6009/6969c.png)
Step 3:
tan C cannot be determined as C is the right angle. The opposite side and hypotenuse of the triangle would be the same.
So sin B also has a value of
This is option A.