100 POINTS -- MEGA POINTS __ CAN CHAT L8R

Type the correct answer in the box.
Rewrite the quadratic equation in the form y = a(x − h)2 + k.
y=5x²-30x+95

y = 5(x - 3)^2 + 50

Step-by-step explanation:

The problem wants you to rewrite the quadratic equation in the vertex form y = a(x - h)^2 + k

You are given a quadratic equation in standard form (ax^2 + bx = c).

To convert from standard form to vertex form, there are two ways but I will show you the easier(?) way.

Use the formula x = -b/2a to find the x-value (h) of the vertex. Note that the vertex in "vertex form" is (h, k) which is virtually the same as (x, y).

In y = 5x^2 - 30x + 95, a = 5, b = -30, and c = 95. Substitute a and b into the formula -b/2a.

-(-30) / 2(5)

Two negative make a positive, so -(-30) becomes 30 and 2 times 5 is 10. Now we have:

30/10 which simplifies down to 3.

The x (h) value of the vertex is 3. To find the y-value, substitute 3 into the original standard form equation.

y = 5(3)^2 - 30(3) + 95

= 5(9) - (90) + 95

45 - 90 + 95

50

The y (k) value of the vertex is 50. Now we have: (h, k) ⇒ (3, 50).

Substitute the values for h and k into the vertex form.

y = a(x - 3)^2 + 50

We still need the a-value, and this is easy to find. You take the a value from the original standard for equation (remember: ax^2 + bx + c)

So our a-value is 5. Now we can substitute this value into the vertex form and complete the question.

y = 5(x - 3)^2 + 50

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v