Sang Jae walks a certain distance due north and then the same distance plus a further 7 km due east. If the final distance from the starting point is 17 km, find the distances he walks north and south

8 Km towards north and 15 Km towards east.

Step-by-step explanation:

On the paper we define directions as -

The figure below illustrates the movement of Sang Jae.

Let he walked x Km distance towards north.

Distance towards east will be x + 7 Km

Given that the distance from origin to the final point is 17 Km.

As the triangle OAC is right angle triangle so

Eliminating the negative value we get x = 8 Km.

So, Sang walked towards north = 8 Km.

And towards East = 8 + 7 = 15 Km.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?