The sum of three consecutive intergers is 267. What is the largest integer

90

Step-by-step explanation:

Let the starting number be x, the two consecutive numbers after x is gonna be x+1 and x+2.

If the sum of these three numbers is 267 then:

x+(x+1)+(x+2)=267

Solve

3x+3=267

3x=267-3

3x=264

x=264/3

x=88

x+1=89

x+2=90

Your three consecutive numbers are 88, 89, and 90.

The largest one of them is 90.

88+89+90=267

Step-by-step explanation:

To do this just divide 267/3 and you get 89, you just look for the previous number (88) and the top number (90) and the sums.

88.89.90

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.