What are the solutions of 4x^2+16x=9

Step-by-step explanation:

Ethan, this is a quadratic equation.  We should rewrite this in standard quadratic form:  4x^2 + 16x - 9 = 0.  Let's use the quadratic formula approach to solve this:

The coefficients of x are a = 4, b = 16 and c = -9.  Thus, the discriminant is

b^2 - 4ac, or 16^2 - 4(4)(-9), or 256 - 144, or 112.

The two solutions are real and are as follows:

       -16 ± √112            -16 ± √(16*7)         -16 ± 4√7

x =   = =

            2(4)                            8                        8

Or, after simplification,

       -4 ± √7

x =

             2

step-by-step explanation: