Sally has $200 in her savings account last month. She added $35 this month and earned $0.75 interest. What is the percent of the increase in the amount in her savings account to the nearest tenth percent? *

The percentage increase in the amount in her savings is 17.9%

Step-by-step explanation:

The formula for percentage increase is given as,  

In previous month, amount of saving in Sally’s account was $200.  

In the current month she added $35 and earned an interest of $0.75. So the total earning in current month will be,  

Total earning = Amount in previous month + Amount added + Interest earned  

Total earning = $ 200 + $ 35 + $ 0.75  

Total earning = $235.75

So, current month amount of saving in account is $ 235.75 which becomes new value and previous month balance that is $ 200 becomes old amount.  

Therefore, New value = $ 235.75 and Old value = $ 200  

Substituting the values in the formula,  

Rounding to nearest tenth means one digit after the decimal place. So, percentage increase is 17.9 %

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}