If a cell undergos cell division every five minutes, how many cells will there be after 1 hour?

4096

Step-by-step explanation:

there are 12 5 minute periods in one hour so

1•2=2 =5m

2•2=4 =10m

4•2=8 =15m

8•2=16 =20m

16•2=32 =25m

32•2=64 =30m

64•2=128 =35m

128•2=256 =40m

256•2=512 =45m

512•2=1024 =50m

1024•2=2048 =55m

2048•2=4096 =60m

4096

Step-by-step explanation:

apperently every 5 min, the cell will start to divide in what can be assumed in this case by factors of 2.

in 5 min, the cell divides into 2. In 10 min, the cell divides into 4. so on and so forth. So, when dividing an hour there are 12 groups of 5 min to complete an hour or 60 min.

Problem: 2^12

4096

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

english maybe i can ..