The height of a volleyball, h, in feet, is given by h = −16t2 + 11t + 5.5, where t is the number of seconds after it has been hit by a player. The top of the net is 7.3 feet above the floor. Does the volleyball travel high enough to clear the top of the net?

It will travel high enough

Step-by-step explanation:

Find the vertex of the parabola:

x=-b/2a

x=-11/2(-16)

x=-11/-32

x=11/32

Plug x=11/32 into quadratic to get the y-coordinate:

h=-16(11/32)^2+11(11/32)+5.5

h=7.391

Since 7.391>7.3, the volleyball will travel high enough (aka. yes)

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2