Mathematics, 18.03.2020 22:27 bryan9892
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
Answers: 3
Mathematics, 22.06.2019 00:00, karinagonzale80
If 7x=9y, y/z = 7/5 , then x/z = (a) 2/7 (b) 7/9 (c) 9/5 (d) 9/7 (e) 5/9
Answers: 1
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠a...
Biology, 07.04.2020 00:16
History, 07.04.2020 00:16
History, 07.04.2020 00:16
Mathematics, 07.04.2020 00:16
Mathematics, 07.04.2020 00:16
Chemistry, 07.04.2020 00:16