Suppose that a phone originally sold for $800 loses 3/5 of its value each year after it is released. After 2 years, how much is the phone worth?
A. $800
B. $1333
C. $128
D. $288

The phone is worth of $128.

Given that the original cost is $800.

After each year it loses 3/5 of its value.

So the cost will be =

Again after 2 years cost will be = .

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After 2 years value of the phone is $128.  option C

Step-by-step explanation:

Given,

Original price of the phone = $ 800

Each year it loses of its value.

To find the value of phone after 2 years.

In 1st years

The value of the phone is= $800 - (800×)

= $ 800-240 = $ 320

In 2nd year

The value of the phone is= $320 - (320×)

= $ 320 - 192 = $ 128

Hence,

After 2 years value of the phone is $128.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

d

step-by-step explanation: