What is the focus of the following graph?

F(1,5)

Step-by-step explanation:

This is a vertical parabola.

The vertex is at (1,4).

The directrix is y=3.

The distance from the vertex to the directrix is p=1

The focus is (1,4+p), which is (1,4+1)

Therefore the focus is (1,5)

6 cm

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube