Consider the sequence {4,6,8,10,...} find the 130th term of the sequence

262

Step-by-step explanation:

Step 1:

To find the nth term of a sequence the basic formula is

Sn = (n*d) + (a-d)

Whereas

Sn= nth Term

n= Term to be found

d= Difference between the terms in the sequence

a= First term in the sequence

Step 2:

Sn = (130*2) +(4-2)

= 260+2

Sn= 262

The nth term for the given problem is 262

what is the rest of the question? ?