If you roll two fair six-sided dice, what is the probability that a least one dice shows a 3?

11/36

Step-by-step explanation:

So here’s the probability of rolling one three or more on one dice:

2,3

1,3. 5 chance of at least one 3 on this dice

4,3

5,3

6,3

On other die:

3,2

3,4

3,1

3,5

3,6. 6 chance of rolling at least one 3 on this dice

3,3

5+6=11

11/36 possible combinations contain at least one three

Hope this helps!

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation: