Math school is selling tickets to a play on the first day of ticket sales the school sold two adult tickets and three students tickets for a total of $57 the school took and $70 on the second day by selling two adult tickets and four student tickets what is the price each of one adult ticket and one student ticket

the cost of an adult ticket is $9.

The cost of a child's ticket is $13

Step-by-step explanation:

Let x represent the price of one adult ticket.

Let y represent the price of one student ticket.

On the first day of ticket sales, the school sold two adult tickets and three students tickets for a total of $57. It means that

2x + 3y = 57- - - - - - - - - -1

The school took and $70 on the second day by selling two adult tickets and four student tickets. It means that

2x + 4y = 70- - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- y = - 13

y = 13

Substituting y = 13 into equation 1, it becomes

2x + 3 × 13 = 57

2x + 39 = 57

2x = 57 - 39 = 18

x = 18/2

x = 9

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".