Henry’s age is 10 years less than 4 times Paul’s age. If the sum of their ages is equal to 25 years, find the age of each boy.

18 yrs and

7 years

Step-by-step explanation:

Let Henry’s age be A and Paul’s age be B

Given Henry’s age A is 10 yrs less than 4 times Paul’s age B.

That’s

A =4 x B - 10

A = 4B - 10

The sum of their ages is equal to 25

That’s

A + B = 25

Therefore,we no now have to equations

1. A = 4B - 10

2. A + B = 25

Now put 4B - 10 in place of A in equation 2

We have

A + B = 25

4B - 10 + B = 25

This can also be written as

4B + B - 10 = 25

5B - 10 = 25

Add 10 to both sides

5B - 10 + 10 = 25 + 10

5B = 35

Divide both sides by 5

5B/5 = 35/5

B = 7

Paul’s age = 7 yrs

Recall A = 4B - 10

and B= 7

Therefore,

A = 4 x 7 - 10

A = 28 - 10

A = 18

Henry’s age = 18 yrs

Their ages are 18 yrs and 7 years

$9.41

step-by-step explanation:

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.