Jeff has $1.35 in nickles and dimes. He has a total of 15 coins. How many of each coin does he have?

For this case we propose a system of equations.

We know that a dime equals 10 cents and a nickel equals 5 cents.

So:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of nickels

According to the statement we have:

We multiply the first equation by -0.10:

We have the following equivalent system:

We add the equations:

So, Jeff has 3 nickels

Jeff has 12 dimes.

12 dimes and 3 nickels

answer: ouch. thats difficult

step-by-step explanation:

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58