A soft drink machine outputs a mean of 25 ounces per cup. The machine's output is normally distributed with a standard deviation of 4 ounces. What is the probability of putting less than 33 ounces in a cup

the probability of putting less than 33 ounces in a cup is 0.98

Step-by-step explanation:

Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = outputs of the machine.

µ = mean output

σ = standard deviation

From the information given,

µ = 25 ounces

σ = 4 ounces

The probability of putting less than 33 ounces in a cup is expressed as

P(x < 33)

For x = 33,

z = (33 - 25)/4 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.98

47 - 90 = 43

43 - 180 = x

x = 137

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