A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.4 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. LOADING... Click the icon to view the display from technology. What are the null and alternative hypotheses? A. Upper H 0: muequals2.4 miles Upper H 1: muless than2.4 miles B. Upper H 0: muless than2.4 miles Upper H 1: muequals2.4 miles Your answer is not correct. C. Upper H 0: muequals2.4 miles Upper H 1: munot equals2.4 miles D. Upper H 0: muequals2.4 miles Upper H 1: mugreater than2.4 miles This is the correct answer. Identify the test statistic. nothing (Round to two decimal places as needed.)

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

c

c

c

c

c

c

c

cc

c

step-by-step explanation:

umumumumum

im not sure

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v