A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 2626 components and accept the whole batch if there are fewer than 3 defectives. If a particular shipment of thousands of components actually has a 77% rate of defects, what is the probability that this whole shipment will be accepted? Round to three decimal places.

Question is not well presented;

Question;

A company purchases shipments of machine components and uses this acceptance sampling plan: Randomly select and test 26 components and accept the whole batch if there are fewer than 3 defectives. If a particular shipment of thousands of components actually has a 7% rate of defects, what is the probability that this whole shipment will be accepted? Round to three decimal places.

0.727

Step-by-step explanation:

Given

n = 26

Let P(D) = Probability of defection

P(D) = 7% = 0.07

The whole batch are to be accepted, if there are fewer than 3 defectives; so, we are looking for P(0≤x≤2).

This is binomial.

Solving the above binomial problem;

We have

P(0≤x≤2) = binomcdf(26,0.07,2)

P(0≤x≤2) = 0.7272

P(0≤x≤2) = 0.727 --- Approximated

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.