"Suppose that allele D produces long toes and allele d produces normal toes. A heterozygous male with the Dd genotype mates with a homozygous female with the dd genotype. Long toes is an autosomal dominant trait expressed with 60 % penetrance. Determine the probability that their offspring will have long toes. Report your answer as a percentage without decimal points."

30%

Step-by-step explanation:

The crossing of a male with genotype Dd with a female with genotype dd, yields the following possible outcomes:

Dd, dD, dd, dd.

Therefore, there is a 2 in 4, (50%) chance that their offspring will have the dominant allele. Since its penetrance is 60%, the dominant trait will only manifest itself in 60% of heterozygous individuals. Therefore, the probability that their offspring will have long toes is:

The probability is 30%.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

two data sets with the same median will not have the same varaibility

step-by-step explanation: