4. Assume that women's heights are normally distributed with a mean given by μ=63.5 in. and a standard deviation given by σ=2.5 in. a. If 1 woman is randomly selected, find the probability that her height is less than 64 in. b. If 34 women are randomly selected, find the probability that they have a mean height less than 64 in.

a) 57.93% probability that her height is less than 64 in

b) 87.90% probability that they have a mean height less than 64 in.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , the sample means with size n of at least 30 can be approximated to a normal distribution with mean and standard deviation

In this problem, we have that:

a. If 1 woman is randomly selected, find the probability that her height is less than 64 in.

This is the pvalue of Z when X = 64.

has a pvalue of 0.5793

57.93% probability that her height is less than 64 in

b. If 34 women are randomly selected, find the probability that they have a mean height less than 64 in.

Now we have

This is the pvalue of Z when X = 64.

By the Central Limit Theorem

has a pvalue of 0.8790

87.90% probability that they have a mean height less than 64 in.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

it would open into a square depending on the type of envelope i’m not sure about the second part