What is the equation of the line parallel to 3x + 2y = -4 that goes through the point (4, -1)?

y=-3/2x+5

Step-by-step explanation:

3x + 2y = -4

2y=-4-3x /:2

y=-4/2-3x/2

y=-3/2x-2

Slope=-3/2(=m) , because this line is parallel slope is the same, then

y-y1=m(x-x1) ,where

A(4,-1) x1 =4, y1 =-1

y-(-1)=-3/2(x-4)

y+1=-3/2x+3/2*4

y+1=-3/2x+6

y=-3/2x+6-1

y=-3/2x+5

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.