The length of a rectangle is 2m more that it's width. The perimeter is 60m. What is its width?

The width is 14m

Step-by-step explanation: The question has provided the perimeter as 60. The available clues are such that the length measures 2m more than it's width. This means whatever is the width of the rectangle, the length shall be equal to plus 2. Hence, if the width is W, the length is W + 2.

So we have,

Perimeter = 60

Length = W + 2 and

Width = W

Already the perimeter is given as

Perimeter = 2(L + W)

We can now express the perimeter as follows;

60 = 2(W + 2 + W)

60 = 2(2 + 2W)

By cross multiplication we now have

60/2 = 2 + 2W

30 = 2 + 2W

Subtract 2 from both sides of the equation

28 = 2W

Divide both sides of the equation by 2

14 = W.

Remember that the length is given as W + 2, so the length becomes

14 + 2 = 16

Therefore, the width equals 14 m.

Step-by-step explanation:

Width = x

Length = x +2

Perimeter = 60 m

2*(length + width) = 60

2*(x + 2 + x) = 60

2*(2x + 2) = 60

    2x + 2 = 60/2

    2x + 2 = 30

          2x = 30-2

          2x = 28

           x = 28/2

          x = 14

Width = 14 m

Length = 14+ 2 = 16 m

250

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet