Question 1

Line one has the equation 2x - 3y = 9 and line two has
the equation - 3x + 2y = -6.
Find the point of intersection for the two lines.
Enter as ordered pair: (1, 2)

The point of intersection of given two lines is (0,-3).

Step-by-step explanation:

Given,

Two equations are

2x-3y = 9 eq 1

-3x+2y = -6 eq 2

To find the point if intersection of these to lines that is to find the value of x and y

Now,

6x-9y = 27 eq1 ×3

-6x+4y = -12 eq 2 × 2

Adding these two equations we get,

(6x-9y)+(-6x+4y) = 27+(-12)

or, -5y = 15

or, y = -3

Putting the value of y in eq 1 we get,

2x = 9 + 3×(-3)

or, 2x = 0

or, x = 0

Hence the point of intersection is (0,-3)

it should be a and d. lmk if i'm wrong xd